Hanley Ramirez Batting Second, Mookie Betts Seventh For Red Sox Vs. Twins

by abournenesn

Jun 4, 2015

The Boston Red Sox are shaking things up.

After an anemic showing in a 2-0 loss to the Minnesota Twins on Wednesday night, the Red Sox’s lineup will look a bit different for Thursday’s series finale at Fenway Park.

Left fielder Hanley Ramirez is back in the lineup but will bat second for the first time this season, while center fielder Mookie Betts will hit seventh for the second consecutive game. Betts has just one hit in his last three games.

Shortstop Xander Bogaerts moves up to fifth in the Red Sox’s batting order, perhaps as a reward for tallying eight hits in his last four contests. Third baseman Pablo Sandoval will take Bogaerts’ place in the six hole.

Rusney Castillo returns to the lineup batting ninth and playing right field, while Blake Swihart will bat eighth and catch for knuckleballer Steven Wright.

Check out the lineups for Thursday’s afternoon slate below.

RED SOX (24-30)
Dustin Pedroia, 2B
Hanley Ramirez, LF
David Ortiz, DH
Mike Napoli, 1B
Xander Bogaerts, SS
Pablo Sandoval, 3B
Mookie Betts, CF
Blake Swihart, C
Rusney Castillo, RF

RHP Steven Wright (2-2, 3.90 ERA)

TWINS (31-21)
Brian Dozier, 2B
Torii Hunter, DH
Joe Mauer, 1B
Trevor Plouffe, 3B
Eddie Rosario, RF
Eduardo Escobar, SS
Kurt Suzuki, C
Shane Robinson, RF
Aaron Hicks, CF

LHP Tommy Milone (2-1, 4.76 ERA)

Thumbnail photo via Tim Heitman/USA TODAY Sports Images

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