Stephen Drew In Lineup; Xander Bogaerts Out For Red Sox Vs. Indians

Stephen Drew is finally back in the Boston Red Sox’s lineup, but it will come at the expense of Xander Bogaerts.

Drew will play shortstop and bat eighth in Boston’s series finale against the Cleveland Indians at Fenway Park on Sunday afternoon after missing the previous six games with a right oblique injury.

The hot-hitting Brock Holt will stay in the leadoff spot for Boston and move to third base, meaning that Xander Bogaerts will sit out for the second time in the last four days.

Taking over Holt’s previous spot in right field is Grady Sizemore, who will bat seventh. Also returning to the lineup is Daniel Nava, who will get the start in left field and bat fifth.

Brandon Workman will take the mound for the Sox after allowing just one hit over 6 2/3 innings in his last outing against the Baltimore Orioles.

Check out both full lineups below.

Boston Red Sox (31-37)
Brock Holt, 3B
Dustin Pedroia, 2B
David Ortiz, DH
Mike Napoli, 1B
Daniel Nava, LF
A.J. Pierzynski, C
Grady Sizemore, RF
Stephen Drew, SS
Jackie Bradley Jr. CF

Brandon Workman, RHP (1-0, 2.86 ERA)

Cleveland Indians (34-35)
Michael Bourn, CF
Asdrubal Cabrera, SS
Michael Brantley, LF
Jason Kipnis, 2B
Lonnie Chisenhall, 3B
Nick Swisher, DH
David Murphy, RF
Carlos Santana, 1B
Yan Gomes, C

Corey Kluber, RHP (6-4, 3.35 ERA)