Rob Gronkowski nearly took his talents home.
Prior to agreeing to a new one-year contract with the Tampa Bay Buccaneers, the veteran tight end considered signing a similar deal with the Buffalo Bills, according to NFL insider Michael Silver.
Gronkowski’s new Buccaneers contract will pay him up to $10 million, NFL Media’s Ian Rapoport reported Monday.
Buffalo finished first in the AFC East in 2020 with a 13-3 record. If the Bills ending the New England Patriots’ reign atop the division wasn’t painful enough for Gronkowski’s former team, Buffalo would have inflicted a double blow by signing him.
But it wasn’t meant to be.
Gronkowski will stay put in Tampa, where he’ll team up with Tom Brady for an 11th season with hopes of defending the Buccaneers’ Super Bowl championship in 2021.